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Question

Precalculus Vector Word problem

A box is on the side of a hill inclined at 30°. The weight of the box is 40 pounds. What is the magnitude of the force required to keep the box from sliding down the hill?

Answer

mgsin(theta) = (40 pounds)*(.453592 kg/1 pound)*(9.8 m/s^2)*sin(30 deg)

                     = 96.744 N